Logic Design

[modena]

I was wondering if anyone here knew how to solve this problem:
F(A,B,C,D) = A'B'D + A'BCD + AC'D' + AC
Implement this using 8:1 Mux using A,B,C as select line (A is MSB and C is LSB). Implement using Mux8.

[BADFlSH]

You probably already have this but I think it is something like
A(C'D'+C) + A'(B'D+BCD)
AB(C'D'+C)+AB'(C'D'+C)+A'B(CD)+A'B'(D)
ABC(1)+ABC'(D')+AB'C(1)+AB'C'(D')+A'BC(D)+A'BC'(0)+A'B'C(D)+A'B'C'(D)

so it looks something like


______
D--|000 |
D--|001 |
0--|010 |
D--|011 |
D'--|100 |
1--|101 |
D'--|110 |
1--|111 |
|______|
|
ABC
I wouldn't be surprised if I made a mistake in there somewhere but I think it is close :)