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sizemic1
11-15-2004, 11:42 AM
This seems lame to me that I can't remember how to do this..but here's the question.

Tan2(theta) = 3.664

How do I solve for theta?

I know tan^-1 3.664 = 74 Degrees
Does this mean theta is half of 74?
This doesn't sound right to me.

Airencracken
11-15-2004, 12:19 PM
You have to use a fudamental property of Trig eqn's.
Tan 2(theta)= 2tan(theta)/(1-tan^2(theta))
:)

sizemic1
11-15-2004, 12:28 PM
Ok..that's not helping :)

Airencracken
11-15-2004, 12:39 PM
okay wait, is it Tan^2(theta) or is it Tan(2(theta))

sizemic1
11-15-2004, 12:42 PM
Tan(2Theta)

Airencracken
11-15-2004, 12:45 PM
Is there a restraint on the domain at all?

ski
11-15-2004, 12:48 PM
Tan2(theta) = 3.664

How do I solve for theta?

I know tan^-1 3.664 = 74 Degrees
Does this mean theta is half of 74?

If you mean that it's tan(2*theta) = 3.664...

tan(2*theta) = 3.664
2*theta = tan^-1(3.664)
theta = tan^-1(3.664) / 2